In a $\Delta ABC$,$\angle A = 30^\circ$ and $a = 8 \text{ cm}$,then the distance of the orthocentre from vertex $A$ is equal to (with usual notations).

  • A
    $4 \text{ cm}$
  • B
    $8 \text{ cm}$
  • C
    $8\sqrt{3} \text{ cm}$
  • D
    $4\sqrt{3} \text{ cm}$

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